The correct option is A (CH3)2CH−CH2−CH2−CH(CH3)2
Wurtz reaction is the reaction of symmetrical alkyl halide in presence of Na and dry ether to give even and symmetrical alkane as product.
Hence, symmetrical alkane with even number of alkane will be a good yield of Wurtz reaction.
Alkane in option b is even and symmetrical alkanes and hence it can be obtained in good yield by Wurtz reaction.
(CH3)CH−CH2−Cl+2Na+Cl−CH2−CH(CH3)2dry ehther−−−−−−→(CH3)2−CH2−CH2−CH(CH3)2
a, c and d are unsymmetrical alkane and thus they cannot be prepared in good yield by Wurtz reaction. Hence, correct option is b.