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Hyperconjugation

Which of the ...

Question

Which of the following alkenes will show maximum number of hyperconjugation?

C H_{2} = C H_{2}

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C H_{3} - C H = C H_{2}

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C H_{3} - C H_{2} - C H = C H_{2}

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C H_{3} - C H_{3} - C H - C H = C H_{2}

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Solution

The correct option is C $C H_{3} - C H = C H_{2}$
Maximum number of hyper conjugations are shown, if the number of hydrogens attached adjacent to $s p^{2}$ hybridised carbon.
$C H_{2} = C H_{2} ⟹$ 0 H.C.
$C H_{3} - C H = C H_{2} ⟹$ 3 H.C.
$↓ s p^{2}$
3 hydrogen
$C H_{3} - C H_{2} - C H = C H_{2} ⟹$ 2 H.C.
$↓ s p^{2}$
2 hydrogen
So, $C H_{3} - C H = C H_{2}$ has high hyper conjugation structures.

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Similar questions

A g N O_{3}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} | C H - C H_{3}

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

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C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

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