Which of the following anions is the weakest base?

C_{2} H_{5} O^{-}

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N O_{3}^{-}

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F^{-}

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C H_{3} C O O^{-}

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Solution

The correct option is B $N O_{3}^{-}$
Weakest Base $\to$ Strongest Conjugate Acid
$C_{2} H_{5} O^{-} \to C_{2} H_{5} O H$

$N O_{3}^{-} \to H N O_{3}$

$F^{-} \to H F$

$C H_{3} C O O^{-} \to C H_{3} C O O H$

Among the given acids, $H N O_{3}$ is the strongest acid.

$∴ N O_{3}^{-}$ is the weakest base.

Option B is correct.

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Similar questions

pOH = 7 - 0.5 p K_{a} + 0.5 p K_{b}

F^{-} = 10; S O_{3}^{2 -} = 100; N O_{3}^{-} = 50

F^{-} = 10; S O_{4}^{2 -} = 100; N O_{3}^{-} = 50

p p m

F^{-} = 10, S O_{4}^{2 -} = 100, N O_{3}^{-} = 50

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