Which of the following are arranged in increasing order of solubilities?

C a C O_{3} < K H C O_{3} < N a C H O_{3}

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N a C H O_{3} < K H C O_{3} < C a C O_{3}

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K H C O_{3} < N a H C O_{3} < C a C O_{3}

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C a C O_{3} < N a H C O_{3} < K H C O_{3}

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Solution

The correct option is D $C a C O_{3} < N a H C O_{3} < K H C O_{3}$
The solubility of bicarbonates of alkali metals increases down the group. but alkaline earth metal carbonates are insoluble in $H_{2} O$

Hence, Option :D: is the correct answer.

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Similar questions

N a H C O_{3}, K H C O_{3}, M g (H C O_{3})_{2}, C a (H C O_{3})_{2}

$N a_{2} C O_{3}$ can be manufactured by Solvay process but $K_{2} C O_{3}$ cannot be prepared because:

N a H {C O}_{3}

K H {C O}_{3}

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