Which of the following can conduct electricity in a fused state?

M g C l_{2}

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C a C l_{2}

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B a C l_{2}

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B e C l_{2}

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Solution

The correct options are
A $C a C l_{2}$
B $M g C l_{2}$
C $B a C l_{2}$
In fused state, ionic compounds have free cations and anions which can move easily to conduct electricity. $M g C l_{2}, C a C l_{2}$ and $B a C l_{2}$ are ionic in nature. So, they can conduct electricity.
However, $B e C l_{2}$ has a covalent character due to small size of Beryllium. In a fused state, $B e C l_{2}$ exists in polymeric state. So, it does not have free ions to conduct electricity.

Option A, B and C are correct.

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Similar questions

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e {C l}_{2}, M g {C l}_{2}, C a {C l}_{2}

B a {C l}_{2}

B e C l_{2}, S r C l_{2}, M g C l_{2}, C a C l_{2}, B a C l_{2}

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

B a C l_{2}

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