Which of the following can exist in enantiomeric forms?

C H_{3} - C H (C H_{3}) - C O O H

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C H_{3} - C H = C H - C H_{2} - C H_{3}

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C H_{3} - C H (N H_{2}) - C H_{3}

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C H_{3} - C H_{2} - C H (O H) - C H_{3}

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Solution

The correct option is D $C H_{3} - C H_{2} - C H (O H) - C H_{3}$
Above all the given compounds, only compound D have chiral center because it the central carbon atom is attached to all different groups. Therefore it can exist as enantiomer.
Hence the correct option is D.

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Similar questions

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

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