Which of the following choices both show the correct order of elements by increasing atomic radius AND by increasing ionization energy?

A l, S, C l

and

A l, S, C l

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A l, S, C l

and

C l, S, A l

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C l, S, A l

and

C l, S, A l

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C l, S, A l

and

A l, S, C l

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Solution

The correct option is D $C l, S, A l$ and $A l, S, C l$
The atomic radius decreases towards the right along period towards the right as the effective nuclear charge increases and due to the same reason the IE increases towards the right. Hence the correct order is $C l, S, A l$ and $A l, S, C l$ i.e., option D.

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Similar questions

Which of the following is the correct sequence for atomic radii

A l {C l}_{3} + {C l}^{-} ⟶ {[A l {C l}_{4}]}^{-}

A l {C l}_{3}

A l {C l}_{3} + {C l}^{-} = A l {C l}_{4}^{-}

A l {C l}_{3}

In $A l_{2} C l_{6}$ , which statement is incorrect-

I

A l > S i > P > C l

I I

B e < M g < C a < S r

I I I

I < B r < C l < F

I V

{N a}^{+} < {M g}^{2 +} < {A l}^{3 +} < {S i}^{4 +}

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