Which of the following complex compounds will not exhibit geometrical isomerism?

[C o (N H_{3})_{4} (H_{2} O) C l] S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (N H_{3})_{3} C l_{3}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{2} [P t B r_{2} C l_{2}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{2} [N i B r_{2} C l_{2}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $K_{2} [N i B r_{2} C l_{2}]$
$[C o (N H_{3})_{4} (H_{2} O) C l] S O_{4}$ and $[C o (N H_{3})_{3} C l_{3}]$ have octahedral geometry and $K_{2} [P t B r_{2} C l_{2}]$ has square planar geometry. So, all of them can show geometrical isomerism. But, $K_{2} [N i B r_{2} C l_{2}]$ has a tetrahedral geometry which cannot show geometrical isomerism.

Suggest Corrections