Question

Which of the following complex has $s{p}^3$ hybridization?

• A. $K_2\left[Ni\right(CN{)}_4]$
• B. $K_4\left[Fe\right(CN{)}_6]$
• C. $\left[Ni\right(N{H}_3{)}_{2}C{l}_2]$
• D. $K_4\left[Ni\right(CN{)}_4]$

Answer 1

The correct option is D $K_4\left[Ni\right(CN{)}_4]$

$K_2\left[Ni\right(CN{)}_4]$: $CN$ is a strong ligand thus form low spin complex and cause pairing of electrons in $N{i}^{2+}$ and forms $ds{p}^2$ hybridized complex.

$K_4\left[Fe\right(CN{)}_6]$: $CN$ is a strong ligand thus form low spin complex and cause pairing of electrons in $F{e}^{2+}$ and forms $d^{2}s{p}^3$ hybridized complex.

$\left[Ni\right(N{H}_3{)}_{2}C{l}_2]$: $N{H}_3$ and $Cl$ are strong and weak ligand thus form low spin complex and cause pairing of electrons in $N{i}^{2+}$ and forms $ds{p}^2$ hybridized complex.

$K_4\left[Ni\right(CN{)}_4]$: $CN$ is a strong ligand thus form low spin complex and cause pairing of electrons in $N{i}^0$ and forms $s{p}^3$ hybridized complex.

Thus option D is correct