Which of the following complex with NOT conduct electricity ?

[C r C l {(H_{2} O)}_{5}] C l_{2} . H_{2} O

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[P t {(N H_{3})}_{6}] C l_{4}

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[C r C l_{3} {(H_{2} O)}_{3}] .3 H_{2} O

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[C o {(N H_{3})}_{4}] C l_{2}

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Solution

The correct option is C $[C r C l_{3} {(H_{2} O)}_{3}] .3 H_{2} O$
$[C r C l_{3} {(H_{2} O)}_{3}] .3 H_{2} O$
This doesn't give any ion in solution so it is non conductor.
Others
$[P t (N H_{3})_{6}] C l_{4}$ gives 5 ions.
$[C r C l (H_{2} O)_{5}] C l_{2} . H_{2} O$ gives 3 ions.
$[C o (N H_{3})_{4}] C l_{2}$ gives 3 ions.
So they all conduct electricity due to these ions.

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Similar questions

When 0.2 mol $C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , 0.4 mol of AgCl are obtained. The formula of the complex is

C r C l_{3} .6 H_{2} O

A g N O_{3}

[P t (N H_{3})_{6}] C l_{4}

[C o {({N H}_{3})}_{4} {C l}_{2}] {N O}_{2}

[C o {({N H}_{3})}_{4} C l {N O}_{2}] C l

[C o {(N H_{3})}_{4} {C l}_{2}] N O_{2}

[C o {(N H_{3})}_{4} C l N O_{2}] C l

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