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Equivalent, Molar Conductivity and Cell Constant

Which of the ...

Question

Which of the following complexes has lowest molar conductance?

C o C l_{3} . 3 N H_{3}

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C o C l_{3} . 4 N H_{3}

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C o C l_{3} .5 N H_{3}

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C o C l_{3} .6 N H_{3}

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Solution

The correct option is A $C o C l_{3} . 3 N H_{3}$
Cobalt has six secondary valences holding ammonia molecules to itself. The three $C l^{-}$ ions and 3 ammonia ions are bound by secondary valences and are not ionisable and will not be precipitated by the addition of $A g N O_{3}$ .
Therefore, the complex behaves as neutral non-conducting molecule. It may be formulated as $[C o (N H_{3}) 3 {C l}_{3}]$ and does not ionise .

Hence it has low conductance as compared to others whoch has extra ammonia ions so as to form precipitate..

Suggest Corrections

Similar questions

Q. Draw Werner's structure of the following:
(a)

C o C l_{3} . 6 N H_{3}

(b)

C o C l_{3} . 5 N H_{3}

(c)

C o C l_{3} . 4 N H_{3}

(d)

C o C l_{3} . 3 N H_{3}

Q. The correct order of the stoichiometries of

A g C l

formed when

A g N O_{3}

in excess is treated with the complexes:

C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}

respectively is:

Th correct order of the stochiometrics of AgCl formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is

Q. Given the molecular formula of the hexa coordinated complexes (A)

{C o C l}_{3} . {6 N H}_{3}

(B)

{C o C l}_{3} . {5 N H}_{3}

(C)

{C o C l}_{3} . {4 N H}_{3}

. If the number of coordinated

{N H}_{3}

molecules in

A, B

and

C

respectively are

6, 5

and

4

, primary valency in

(A), (B)

and

(C)

are

Q. Which of the following complexes has the least molar conductivity in the solution?

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