Which of the following compound are optically active
$a = O C H_{3}, b = N H C O C H_{3}, C = C H_{3}, d = C H_{2} C H_{3}$

I

only

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I I I

only

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I

and

I I I

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I I

and

I I I

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Solution

The correct option is C $I$ and $I I I$
If either of the ends of allene is attached to two identical substituents, then it is achiral. It is because it will have plane of symmetry.
If neither of the ends are attached to two identical substituents, then it is chiral.

In case of $I I$ , each of the ends have identical substituents. So it doesn't show optical activity.
$I$ and $I I I$ are optically active.

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{C H}_{3} C H_{2} {C H}_{2} {C H}_{2} {C H}_{3}, {C H}_{3} - {C H}_{3} | C H - {C H}_{2} C H_{3}, {C H}_{3} - {C H}_{3} | C_{3} - {C H}_{3}

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