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Fluorides of Xenon

Which of the ...

Question

Which of the following compound cannot be prepared?

X e F_{2}

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X e F_{3}

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X e F_{4}

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X e F_{6}

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Solution

The correct option is B $X e F_{3}$
Xe has a complete filled 5p configuration. As a result when it undergoes bonding with an odd number (3 or 5) of F atoms it leaves behind one unpaired electron. This causes the molecule to become unstable. As a result $X e F_{3}$ , $X e F_{5}$ not possible.

Only even no. of fluorides can combine with Xe. Therefore $X e F_{3}$ cannot be formed, Only even bonds can be formed.

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Similar questions

X e F_{2}

X e F_{3}

X e F_{5}

X e F_{6}

S b F_{5}

X e F_{4}

X e F_{6}

[X e F_{3}^{+}] [{S b F_{6}}^{-}]

[X e F_{5}^{+}] [{S b F_{6}}^{-}]

X e F_{3}^{+}

[X e F_{5}^{+}]

S b F_{5}

X e F_{4}

X e F_{6}

[X e F_{3}^{+}] [S b F_{6}]^{-} a n d [X e F_{5}^{+}] [S b F_{6}^{-}] .

X e F_{3}^{+}

X e F_{5}^{+}

How are xenon fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ obtained?

s p^{3} d

X e F_{2}, X e F_{4}, X e F_{6}, X e O F_{2}, X e O_{3}

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