Question

Which of the following compound(s) exhibit optical isomerism?

• A.
• B.
• C.
• D.

Answer 1

Answer: (A), (C)

For a molecule to be optically active it should not have plane of symmetry or centre of symmetry.

Compound (b) and (d) has plane of symmetry about the plane of the paper.
Compound (a) and (c) does not have any symmetry in the molecule.
Hence, (a) and (c) exhibit optical isomerism