Which of the following compound(s) is/are paramagnetic?

[N i (C O)_{4}]

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K_{2} [N i (C N)_{4}]

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K_{3} [C o F_{6}]

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[C r (N H_{3})_{6}] C l_{3}

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Solution

The correct option is D $[C r (N H_{3})_{6}] C l_{3}$
1. $[N i (C O)_{4}]$
$N i : 28 : [A r] 3 d^{8} 4 s^{2} N i^{0} : 28 : [A r] 3 d^{10} 4 s^{0}$
$C O$ is a strong field ligand, it forces pairing. Hence, this is diamagnetic.

2. $K_{2} [N i (C N)_{4}]$
$N i : 28 : [A r] 3 d^{8} 4 s^{2} N i^{2 +} : 26 : [A r] 3 d^{8} 4 s^{0}$
$C N^{-}$ is a strong field ligand, it forces pairing. Hence, this is diamagnetic.

3. $K_{3} [C o F_{6}]$
$C o : 27 : [A r] 3 d^{7} 4 s^{2} C o^{3 +} : 24 : [A r] 3 d^{6} 4 s^{0}$
$F^{-}$ is a weak field ligand, it does not force pairing. Hence, this is paramagnetic.

4. $[C r (N H_{3})_{6}] C l_{3}$
$C r : 24 : [A r] 3 d^{4} 4 s^{2} C r^{3 +} : 21 : [A r] 3 d^{3} 4 s^{0}$
$N H_{3}$ is a strong field ligand, it forces pairing. But, there is only 1 unpaired electron. So this is paramagnetic.

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