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Question

Which of the following compound(s) will be optically inactive?

A
H2C=C=CH­2
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B
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C
CH3CH=C=CHCH3
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D
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Solution

The correct options are
A H2C=C=CH­2
B
D
CH2=C=CH2 will be inactive because of the presence of a plane of symmetry as they are planar
Option (b) is inactive because of the presence of a plane of symmetry.
Option (c) is not symmetrical which makes it an optically active compound
Option (d)
the compound is inactive because of internal compensation.


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