Which of the following compound(s) will be optically inactive?
A
H2C=C=CH2
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B
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C
CH3−CH=C=CH−CH3
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D
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Solution
The correct options are AH2C=C=CH2 B D CH2=C=CH2 will be inactive because of the presence of a plane of symmetry as they are planar Option (b) is inactive because of the presence of a plane of symmetry. Option (c) is not symmetrical which makes it an optically active compound Option (d) the compound is inactive because of internal compensation.