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Question
Which of the following compound(s) will not undergo β- Elimination reaction on reacting with alcoholic KOH?
Which of the following compound(s) will not undergo β- Elimination reaction on reacting with alcoholic KOH?
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Solution
The correct option is D
When an alkyl halide is treated with alcoholic KOH ( KOH dissolved in alcohol) it undergoes dehydrohalogenation to give alkene as product.
Removal of the halogen atom together with a hydrogen atom from a carbon adjacent to the one bearing the halogen. Since hydrogen is eliminated from the β− carbon atom, the dehydrohalogenation of alkyl halide is also known as β−Elimination reaction.
So for this particular reaction to proceed there should be a β−hydrogen in the molecule.
In compound (a) and (d), there is no β−hydrogen so they don't undergo elimination reaction in presence of alcoholic KOH.
Compound (b) has 2 β-Hydrogen and compound (c) has 1 β-Hydrogen so they undergo β Elimination.
When an alkyl halide is treated with alcoholic KOH ( KOH dissolved in alcohol) it undergoes dehydrohalogenation to give alkene as product.
Removal of the halogen atom together with a hydrogen atom from a carbon adjacent to the one bearing the halogen. Since hydrogen is eliminated from the β− carbon atom, the dehydrohalogenation of alkyl halide is also known as β−Elimination reaction.
So for this particular reaction to proceed there should be a β−hydrogen in the molecule.
In compound (a) and (d), there is no β−hydrogen so they don't undergo elimination reaction in presence of alcoholic KOH.
Compound (b) has 2 β-Hydrogen and compound (c) has 1 β-Hydrogen so they undergo β Elimination.
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