Which of the following compounds can exhibit both geometrical isomerism and enantiomerism?

C H_{3} - C H = C H = C H_{3}

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C H_{3} C H_{2} - C = C H = C H - C O O K

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C H_{3} C H_{2} - C = C H = C H - C O O H

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C H_{3} - C H O H - C O O H

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Solution

The correct option is B $C H_{3} C H_{2} - C = C H = C H - C O O K$
Geometrical isomerism, also known as cis-trans isomerism is when the compounds contain the same type and number of atoms, bonds and groups but their spatial arrangements are different. Cis isomers have the like groups adjacent to each other, while trans isomers have groups arranged opposite to each other.

Enantiomers, on the other hand, are non-superimposable, chiral compounds that are mirror images of one another.

From the given compounds only compound B can exhibit both geometrical isomerism and enantiomerism.

Hence, the correct answer is option B.

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Similar questions

{C H}_{3} C H_{2} {C H}_{2} {C H}_{2} {C H}_{3}, {C H}_{3} - {C H}_{3} | C H - {C H}_{2} C H_{3}, {C H}_{3} - {C H}_{3} | C_{3} - {C H}_{3}

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C H_{3} - C H = C H - C H_{2} - O H | C H - C H_{3} ⟶ C H_{3} - C H = C H - C H_{2} - C O O H

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