Question

Which of the following compounds has $s{p}^2$-hybridization ?

• A. $C{O}_2$
• B. $S{O}_2$
• C. $N_{2}O$
• D. $CO$

Answer 1

The correct option is B $S{O}_2$

Shown above is the shape of an $S{O}_2$ molecule. Its molecular geometry will be trigonal because of the three valence electron pairs on sulfur, two bonding pairs and a lone pair. This will give it a bent molecular shape. In this molecule, the dipoles are not pointing in opposite directions, and will not cancel out. They will, in fact add, and give a net dipole moment. $S{O}_2$ is a polar compound, which explains its elevated boiling point.

Only $S{O}_2$ will have $s{p}^2$ hybridisation.

For $C{O}_2$ ,it has $sp$ hybridisation.

For $CO$, it has $sp$ hybridisation.