Question

Which of the following compounds will release $C{O}_2$ on reaction with $NaHC{O}_3$?

• A. Hexanol
• B. Phenol
• C. Acetic acid
• D. Acetylene

Answer 1

The correct option is C Acetic acid

Compounds which have higher acidic strength than conjugate acid of sodium bicarbonate (i.e., carbonic acid) will react with $NaHC{O}_3$ to produce $C{O}_2$.
Phenol, hexanol and acetylene are weaker acid compared to carbonic acid so they won't react with $NaHC{O}_3$, whereas acetic acid (contains carboxylic acid group) is more acidic than carbonic acid. Hence it will react with $NaHC{O}_3$ to give $C{O}_2$.
$C{H}_{3}COOH+NaHC{O}_3\to C{H}_{3}COONa+H_{2}O+C{O}_2\uparrow$