Question

Which of the following contains the maximum number of atoms?

• A. $1.0$ g of butane $\left(C_4{H}_{10}\right)$
• B. $1.0$ g of nitrogen $\left(N_2\right)$
• C. $1.0$ g of silver $\left(Ag\right)$
• D. $1.0$ g of water $\left(H_{2}O\right)$

Answer 1

The correct option is A $1.0$ g of butane $\left(C_4{H}_{10}\right)$

No. of atoms of butane= $14\times N_A\times \frac{1}{58}$

No. of atoms of nitrogen = $2\times N_A\times \frac{1}{28}$

No. of atoms of silver = $1\times N_A\times \frac{1}{108}$

No. of atoms of water = $3\times N_A\times \frac{1}{18}$

So butane contains the maximum number of atoms.