Which of the following conversions involves change in both shape and hybridisation?

{C H}_{4} \to C_{2} H_{6}

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{N H}_{3} \to {N H}_{4}^{+}

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H_{2} O \to H_{3} O^{+}

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{B F}_{3} \to {B F}_{4}^{-}

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Solution

The correct option is A ${B F}_{3} \to {B F}_{4}^{-}$
(A) Both $C H_{4}$ and $C_{2} H_{6}$ have $s p^{3}$ hybridisation and tetrahedral shape.

(B) Both $N H_{3}$ and $N H_{4}^{+}$ have $s p^{3}$ hybridisation. But the shape of $N H_{3}$ is pyramidal and shape of $N H_{4}^{+}$ is tetrahedral.

(C) Both $H_{2} O$ and $H_{3} O^{+}$ have $s p^{3}$ hybridisation. $H_{2} O$ is bent shaped molecule and $H_{3} O^{+}$ is pyramidal.

(D) ${B F}_{3} \to {B F}_{4}^{-}$ involves change in both shape and hybridisation. ${B F}_{3}$ is trigonal planar with $s p^{2}$ hybridisation.
${B F}_{4}^{-}$ is tetrahedral with $s p^{3}$ hybridisation.

Hence, option D is correct.

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Similar questions

Which of the following conversions involve change in both shape and hybridisation?

a) CH4 -> C2H6

b) NH3 -> NH4+

c) BF3 -> BF4-

d) H2O ->H3O+

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

{N H}_{4}^{+} + H_{2} O ⇋ {N H}_{3} + H_{3} O^{+}

C H_{4}, N H_{3}, H_{2} O, B F_{3}, C_{2} H_{2}

N H_{3}, N H_{2}^{-}, N H_{4}^{+}

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