Which of the following corresponds to the principal value branch of tan^-1?
(a) $(- \frac{π}{2}, \frac{π}{2}) (b) [- \frac{π}{2}, \frac{π}{2}] (c) (- \frac{π}{2}, \frac{π}{2}) - \{0\} (d) (0, π)$

Open in App

Solution

The principal value branch of tan⁻¹x is $(- \frac{π}{2}, \frac{π}{2})$ .

Hence, the correct answer is option (a).

Suggest Corrections

Similar questions

(- \frac{π}{2}, \frac{π}{2}) (b) [0, π] - \{\frac{π}{2}\} (c) [- \frac{π}{2}, \frac{π}{2}] (d) [- \frac{π}{2}, \frac{π}{2}] - \{0\}

(a) [- \frac{π}{2}, \frac{π}{2}] - \{0\} (b) [0, π] - \{\frac{π}{2}\} (c) (0, π) (d) (- \frac{π}{2}, \frac{π}{2})

\lim_{x \to \frac{π}{2}} (\frac{π}{2} - x) \tan x

B_{2}, C_{2}

N_{2}

a

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} a^{2} - 3 + sin x, & 0 < x < \frac{π}{2} 1 + cos x, & \frac{π}{2} \leq x < π \end{matrix}

x = \frac{π}{2},

Join BYJU'S Learning Program