Which of the following decolourises hot $K M n O_{4}$ solution ?

C H_{3} C H_{2} C H_{3}

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C H_{4}

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C H_{3} C H_{3}

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{(C H_{3})}_{3} C H

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Solution

The correct option is A $C H_{3} C H_{2} C H_{3}$
The heat of combustion of methane, ethane and tert-butane is very high due to which they are not oxidized with $K M n O_{4}$ . Propane, however, has relatively less heat of combustion and thus gets oxidized to $C O_{2}$ and decolorizes $K M n O_{4}$ solution.

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