Which of the following easily reacts with water producing hydrogen ?

P H_{3}

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B_{2} H_{6}

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C H_{4}

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H_{2} S

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Solution

The correct option is B $B_{2} H_{6}$
$B_{2} H_{6}$ is a highly reactive and versatile reagent. It react violently with water to form hydrogen and boric acid.
$B_{2} H_{6} + 6 H_{2} O \to 2 B (O H)_{3} + 6 H_{2} ↑; Δ H = - 466 k J / m o l$

$C H_{4}$ does not react with liquid water but it will react with gaseous water to form carbon dioxide, carbon monoxide and hydrogen. This reaction is endothermic so it needs heat energy for the reaction to take place.

$H_{2} S$ doesnt react with water, it just dissociate as $H S^{-}, S^{2 -} and H^{+}$ in water.

$P H_{3}$ is non polar compound so it doesn't dissolve in water so there is no reaction between them.

Hence, Diborane react easily with water to produce hydrogen.

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Preparation of Hydrogen

Standard XIII Chemistry

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