Question

Which of the following elements cannot exhibit sp${}^3$d hybridization state?

(a) $C$ (b) $P$ (c) $Cl$ (d) $B$

• A. $a,c$
• B. $a,d$
• C. $b,c$
• D. $b,d$

Answer 1

The correct option is B $a,d$

The number of valence electrons in ${}^{\prime }{C}^{\prime }$ is $4$ and ${}^{\prime }{B}^{\prime }$ is $3$. ${sp}^{3}d$ hybridisation involves ${}^{\prime }{5}^{\prime }$ valence shell orbitals.

As $C$ and $B$ does not have d-orbital, they cannot show $s{p}^{3}d$ hybridization.