The correct option is C Na
A big jump in ionisation energy is found when an electron is ejected from a stable inert gas configuration.
The electronic configuration of the given elements are as follows:
P:[Ne]3s23p3
Si:[Ne]3s23p2
Na:[Ne]2s1
Ne:[He]2s22p6
When an electron is ejected from Na, it acquires a noble gas configuration, Na+:[Ne]. Therefore, the second electron requires a huge amount of energy for ejection. Hence, for sodium IE2>IE1.