Which of the following equations corresponds to the definition of enthalpy of formation at 298K?
A
C(graphite)+2H2(g)+12O2(g)⟶CH3OH(l)
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B
2C(graphite)+4H2(g)+O2(g)⟶2CH3OH(l)
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C
C(diamond)+2H2(g)+12O2(g)⟶CH3OH(l)
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D
C(graphite)+2H2(g)+12O2(l)⟶CH3OH(g)
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Solution
The correct option is AC(graphite)+2H2(g)+12O2(g)⟶CH3OH(l)
Graphite is a standard state of Carbon and CH3OH in liquid state is also a standard state. Hence, option A is correct because all the reactants and products must be in standard state.