The correct option is B 5BiO−3+14H++2Mn2+→5Bi3++7H2O+2MnO−4
5BiO−3+14H++2Mn2+→5Bi3++7H2O+2MnO−4
As if this equation has equal sum of charges on both side, so this is balanced.
-5 + 14 + 2* (+2 ) = 5 * (+3) + 7 * 0 + 2 * (-1)
-5 + 14 +4 = 15 + 0 -2
+ 13 = + 13
As both side the sum of the charges of all species is same so this is balanced.