Balance the following redox reaction- HCOOH - MnO4- CO2 - Mn2-

The correct option is A 5HCOOH + 6H^+ + 2MnO_4^ → 5CO_2 + 2Mn^2+ + 8H_2O The balanced redox reaction is : 5HCOOH + 6H^+ + 2MnO_4^ → 5CO_2 + 2Mn^ ...

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Ion Electron Method

Balance the f...

Question

Balance the following redox reaction:
$H C O O H + M n O_{4}^{-} \to C O_{2} + M n^{2 +}$

H C O O H + M n O_{4}^{-} \to C O_{2} + M n^{2 +}

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4 H C O O H + M n O_{4}^{-} \to 2 C O_{2} + M n^{2 +} + H_{2}

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H C O O H + 2 M n O_{4}^{-} \to 2 C O_{2} + M n^{2 +}

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5 H C O O H + 6 H^{+} + 2 M n O_{4}^{-} \to 5 C O_{2} + 2 M n^{2 +} + 8 H_{2} O

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B i O_{3}^{-} + M n^{2 +} \to B i^{3 +} + M n O_{4}^{-} + H_{2} O

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$ the reductant is

C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ which is the reducing agent?

M n O_{4,}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

M n O_{4,}^{-} + C_{2} O_{4}^{-} + H^{+} :

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