Which of the following equations represents the largest ionization energy?

N a_{(g)} \to N a_{(g)}^{+} + 1 e^{-}

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N a_{(g)}^{+} \to N a_{(g)}^{2 +} + 1 e^{-}

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K_{(g)} \to K_{(g)}^{+} + 1 e^{-}

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K_{(g)}^{+} \to K_{(g)}^{2 +} + 1 e^{-}

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Solution

The correct option is B $N a_{(g)}^{+} \to N a_{(g)}^{2 +} + 1 e^{-}$
It is always more difficult to remove electron from a positive species. Also ${N a}^{+}$ has more effective nuclear charge than $K^{+}$ . So IE of ${N a}^{+}$ is more than that of $K^{+}$ . Thus highest IE among $N a, {N a}^{+}, K, K^{+}$ is of ${N a}^{+}$ . Hence correct option is B.

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The decomposition of hydrocarbon follows the equation $k = (4.5 \times 10^{11} s^{- 1}) e^{- 28000} K / T$ . Calculate the activation energy $E_{a}$

The decomposition of hydrocarbon follows the equation

k = (4.5 × 10¹¹s⁻¹) e⁻²⁸⁰⁰⁰^K^/^T

Calculate E_a.

N a F (s)

N a_{(g)} \to N a_{(g)}^{+} + e^{-}

F_{(g)} + e^{-} \to F_{(g)}^{-}

N a_{(g)}^{+} + F_{(g)}^{-} \to N a F_{(s)}

k = (4.5 \times 10^{11} s^{- 1}) e^{- 28000 / K / T}

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