Which of the following gases contain the same number of molecules as that of $16$ g of oxygen?

16

g of

O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32

g of

S O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16

g of

S O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $32$ g of $S O_{2}$
Number of molecules = Number of moles $\times N_{A}$

When two gases have the same number of molecules, they will contain the same number of moles.
Number of moles of a substance= $\frac{g i v e m a s s}{m o l a r m a s s}$

$16$ g of oxygen $(O_{2}$ ) corresponds to $\frac{16}{32} = 0.5$ mole.

$16$ g of $O_{3}$ corresponds to $\frac{16}{48} = 0.33$ mole.

$32$ g of $S O_{2}$ corresponds to $\frac{32}{64} = 0.5$ mole.

$16$ g of $S O_{2}$ corresponds to $\frac{16}{64} = 0.25$ mole.

Hence, option B is correct.

Suggest Corrections

Similar questions

O_{2} a s i n 16 g o f O_{2}

O_{2}

O_{2}

4.4

C O_{2}

0.56

S O_{2}

C = 12, 0 = 16, S = 32

16 g of oxygen has same number of molecules as in

(a) 16 g of CO (b) 28 g of $N_{2}$ (c) 14 g of $N_{2}$ (d) 1.0 g of $H_{2}$

Join BYJU'S Learning Program