Which of the following groups in the given compound will have the highest migratory aptitude?
A
Methyl
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B
Hydride
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C
Phenyl
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D
All shows similar migratory aptitude
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Solution
The correct option is C Phenyl In the given compound, hydride shift is not possible here. Here, both methyl and phenyl shifts are possible because they give tertiary carbocation which is more stable than secondary carbocation. Since the relative migratory aptitude of groups folows the order, Hydride > Phenyl > Methyl The given compound will undergo 1, 2- phenyl shift to form tertiary carbocation.