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Question

Which of the following had maximum valence electrons? (Atomic numbers are given in brackets)


A

Na(11)

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B

N(7)

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C

Mg(12)

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D

Si(14)

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Solution

The correct option is B

N(7)


The correct option is (B).

Explanation of Correct Option:

  1. A number of electrons present in the outermost shell of an atom is called valence electrons.
  2. Atomic number. of Nitrogen (N) is 7 and has the electronic configuration as (2,5).
  3. From the electronic configuration of the nitrogen atom, we come to know that the number of electrons present in the outermost shell i.e., 2nd shell is 5 electrons.
  4. Thus, the total number of valence electrons present in nitrogen atoms is five.

Explanation of Incorrect Options:

Option (A): Na(11)

Atomic number of Sodium (Na) is 11and has it's electronic configuration as (2,8,1). Thus, the total number of valence electrons present in Sodium atoms is one.

Option (C): Mg(12)

Atomic number of Magnesium (Mg) is 12 and has it's electronic configuration as (2,8,2). Thus, the total number of valence electrons present in Magnesium atoms is two.

Option (D): Si(14)

Atomic number of Silicon (Si) is 14 and has it's electronic configuration as (2,8,4). Thus, the total number of valence electrons present in Silicon atoms is four.

Hence, option (B) Nitrogen(N) has the maximum number of valence electrons.


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