Which of the following has a bond formed by overlap of $s p^{3}$ - hybrid orbitals?

C H_{3} - C \equiv C - C H_{3}

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C H_{3} - C H = C H - C H_{3}

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C H_{2} = C H - C H = C H_{2}

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H C \equiv C H

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Solution

The correct option is A $C H_{3} - C \equiv C - C H_{3}$
$C H_{3} - C \equiv C - C H_{3}$ has a bond formed by overlap of $s p^{3}$ hybrid orbitals.

$C H_{3} C H = C H - C H_{3}$ has a bond overlapped by $s p^{3} s p^{2} s p^{2} s p^{3}$ orbital

$C H_{2} = C H - C H = C H_{2}$ has a bond overlapped by $s p^{2}$ orbital.

$H C \equiv C H$ has a bond overlapped by $s p$ orbital.

Hence option A is the corret answer.

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