Which of the following has a octet/duplet electronic configuration?
A
B3−
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
B−
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
B3+
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
B2+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CB3+ The atomic number of Boron =5
Electronic configuration of Boron is: [He]2s22p1
Configuration of valence shell: 2s22p1
It does not have a complete octet.
a) B3−
Electronic configuration of B3− (with 8 electrons) is: [He]2s22p4
Configuration of valence shell: 2s22p4
It does not have a complete octet.
b) B−
Electronic configuration of B− ( with 6 electrons) is: [He]2s22p2
Configuration of valence shell: 2s22p2
It does not have a complete octet.
(c) B3+
Electronic configuration of B3+ (with 2 electrons) is: [He]
Configuration of valence shell: 1s2
Boron is most likely to form B3+ as it forms an inert gas electronic configuration of Helium (satisfying duplet).
(d) B2+
Electronic configuration of B2+ ( with 3 electrons) is: [He]2s1
Configuration of valence shell: 2s1
It does not have a complete octet.