Question

Which of the following has maximum number of atoms?

• A. $10\text{g}$ of $N_2\text{(g)}$ [Atomic mass of $N=14u$]
• B. $10\text{g}$ of $O_2\text{(g)}$ [Atomic mass of $O=16u$]
• C. $10\text{g}$ of $O_3\text{(g)}$ [Atomic mass of $O=16u$]
• D. $10\text{g}$ of $Cu\text{(s)}$ [Atomic mass of $Cu=63.5u$]

Answer 1

The correct option is A $10\text{g}$ of $N_2\text{(g)}$ [Atomic mass of $N=14u$]

(i) Number of $N$ atoms in $N_2=\frac{10}{28}\times 2\times N_A$
(ii) Number of $O$ atoms in $O_2=\frac{10}{32}\times 2\times N_A$
(iii) Number of $O$ atoms in $O_3=\frac{10}{48}\times 3\times N_A$
(iv) Number of $Cu$ atoms in $Cu\left(s\right)=\frac{10}{63.5}\times N_A$