Which of the following has the lowest bond angle ?

N H_{3}

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B e F_{2}

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H_{3} O^{+}

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C H_{4}

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Solution

The correct option is A $N H_{3}$
Consider the hybridization and bond angle of the given options:-
A) $N H_{3}$ - $s p^{3}$ hybridized with 1 lone pair. Hence bond angle approximately $107^{\circ}$ .
B) $B e F_{2}$ - $s p$ hybridized. Bond angle is $180^{\circ}$ .
C) $H_{3} O^{+}$ - $s p^{3}$ hybridized.Bond angle is ${109.5}^{\circ}$ .
D) $C H_{4}$ - $s p^{3}$ hybridized.Bond angle is $109^{\circ} 28^{'}$ .
Hence option A is the right answer.

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