Question

Which of the following has two geometrical isomers, and is also a non ionisable complex?

• A. $Pt{Cl}_4\cdot 2N{H}_3$
• B. $Pt{Cl}_4\cdot 3N{H}_3$
• C. $Pt{Cl}_4\cdot 4N{H}_3$
• D. $Pt{Cl}_4\cdot 6N{H}_3$

Answer 1

The correct option is A $Pt{Cl}_4\cdot 2N{H}_3$

Option (A) is correct. $Pt{Cl}_4\cdot 2N{H}_3$ has two geometrical isomers and is also a non ionisable complex.

The complex $\left[Pt\right(N{H}_3{)}_{2}C{l}_4]$ shows two geometric isomers, that differ in the $Cl-Pt-Cl$ bond angle. The prefix cis identifies the isomer in which two like ligands are on same side of the metal atom, and trans identifies the isomer in which two like ligands are on opposite side of the metal atom. In cis isomer, the $Cl-Pt-Cl$ angle is 90${}^o$ and in the trans isomer it is 180${}^o$. Both the ligands are within the coordination sphere, thus are non -ionisable.