Question

Which of the following have maximum and minimum ionic character out of $MnO,Mn{F}_2,Mn{O}_2,M{n}_2{O}_7$?

• A. $MnO,M{n}_2{O}_7$ respectively
• B. $Mn{F}_2,M{n}_2{O}_7$ respectively
• C. $Mn{O}_2,MnO$ respectively
• D. $M{n}_2{O}_7,MnO$ respectively

Answer 1

The correct option is A $MnO,M{n}_2{O}_7$ respectively

Oxidation states of the Mn in given compounds are:

$MnO-$+2

$Mn{F}_2$ -+2

$Mn{O}_2$- +4

$M{n}_2$O${}_7$ - +7

Higher the oxidation state of the central metal atom, more ionic is the compound. And since F is more electronegative than O, the compound in which Mn has the same oxidation no.'s and F is present. It will be more ionic than the compound which contains $O$

So the most ionic is- $M{n}_2{O}_7$

minimum ionic is - $MnO$.