Which of the following ions will exhibit colour in aqueous solutions?

S c^{3 +} (Z = 21)

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L a^{3 +} (Z = 57)

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T i^{3 +} (Z = 22)

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L u^{3 +} (Z = 71)

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Solution

The correct option is D $T i^{3 +} (Z = 22)$
Unpaired $e^{-}$

In $S c^{+ 3}$ , electronic configuration is $3 d^{o}$ $0$
In $L a^{+ 3}$ , electronic configuration is $[X e] 5 d^{o}$ $0$
In $T i^{+ 3}$ , electronic configuration is $3 d^{1}$ $1$
In $L u^{+ 3}$ , electronic configuration is $f^{14} 5 d^{o}$ $0$

As in $T i^{+ 3},$ number of the unpaired electron is $1$ ; because of which d-d transition takes place which is partly allowed.

Therefore, it exhibits colour in aqueous solution.

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