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Question

Which of the following is a correct graph between object distance(u) and image distance (v) for a concave mirror as per the sign convention?

A
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B
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C
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D
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Solution

The correct option is A
In case of concave mirror for virtual objects, the object distance is +ve and the corresponding image formed will be real (image distance will be -ve)

For real objects,
Both object distance (u) and image distance (v) are negative.

When the object approaches , the image is formed at focus (F).



The graph of u vs v will be never a straight line because
1u+1v=1f
The lines indicating and + will be asymptotic as 1u0 and 1v1f when u
Thus, correct option is (a)

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