Which of the following is a factor of $x^{3} - 5 x^{2} - 2 x + 24 ?$

x-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x+3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x+4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x-4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
x-4

Consider p(x)= $x^{3} - 5 x^{2} - 2 x + 24$

By trial and error method, x = -2 satisfies p(x)

Therefore (x + 2) is one of the factors of p(x)

p(x) = (x +2) $(x^{2}$ -7x +12)

= (x+ 2) (x – 3)(x – 4)

The linear factors of p(x) are (x +2), (x – 3) and (x – 4)

Suggest Corrections

Similar questions

x^{3} - 5 x^{2} - 2 x + 24

x^{3} - 5 x^{2} - 2 x + 24

x^{3} - 5 x^{2} - 2 x + 24 = 0

p (2), p (- 1)

p (x) = x^{3} - 5 x^{2} - 2 x + 24

x^{3} + 5 x^{2} - x - 5

Join BYJU'S Learning Program