Which of the following is an identity ?

(a + b) (a + b) = a^{2} + 2

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(a + b) (a + b) = 4

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(a + b) (a + b) = a^{2} + b^{2} + 2 a b

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(a + b) (a + b) = 1

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Solution

The correct option is C $(a + b) (a + b) = a^{2} + b^{2} + 2 a b$
$(a + b) (a + b) = a (a + b) + b (a + b)$
$= a^{2} + b^{2} + 2 a b = R H S$
so it is true for every value of $a$ and $b$

Suggest Corrections

Similar questions

a = b = 1

a = b

a^{2} = a b

a^{2} - b^{2} = a b - b^{2}

(a + b) (a - b) = b (a - b)

\frac{b (a - b)}{a - b}

a + b = b

1 + 1 = 1

2 = 1

a^{2} - b^{2} = (a + b) (a - b)

1 + 2 a b - (a^{2} + b^{2})

a^{2} - b^{2} = (a + b) (a - b)

1 + 2 a b - (a^{2} + b^{2})

a^{2} + b^{2} - 2 (a b - a c + b c)

= (a - b) {(a - b) + 2 c} = (a - b) (a - b + 2 c)

Simplify $\frac{a - b}{a} + \frac{a + b}{b}$

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