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Byju's Answer
Standard XII
Chemistry
Idea of Hybridisation
Which of the ...
Question
Which of the following is/ are correctly matched?
A
[
N
i
(
C
O
)
4
]
−
d
s
p
2
and diamagnetic
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B
[
N
i
(
e
n
)
3
]
(
N
O
2
)
3
−
s
p
3
d
2
and two unpaired electrons
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C
[
V
(
N
H
3
)
6
]
C
l
3
−
s
p
3
d
2
and two unpaired electrons
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D
[
M
n
(
N
O
+
)
3
(
C
O
)
]
−
s
p
3
and diamagnetic
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Solution
The correct option is
A
[
N
i
(
C
O
)
4
]
−
d
s
p
2
and diamagnetic
Option C is correct.
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0
Similar questions
Q.
Both
[
N
i
(
C
O
)
4
]
and
[
N
i
(
C
N
)
4
]
2
−
are diamagnetic. The hybridisation of nickel in these complexes, respectively are:
Q.
Match the complex ions listed in column-I with the characteristics listed in column-II using the codes given below.
Column-I
Column-II
(a)
[
N
i
(
N
H
3
)
6
]
2
+
(p)
d
2
s
p
3
and diamagnetic
(b)
[
C
r
(
N
H
3
)
6
]
3
+
(q)
s
p
3
d
2
and diamagnetic
(c)
[
C
o
(
N
H
3
)
6
]
3
+
(r)
s
p
3
d
2
and two unpaired electrons
(d)
[
Z
n
(
N
H
3
)
6
]
2
+
(s)
d
2
s
p
3
and three unpaired electrons.
Q.
Assertion :
F
e
+
2
is paramagnetic and Se+ is diamagnetic Reason: Unpaired electrons are present in d subshell of
F
e
+
2
Q.
Assertion :The atoms or ions possessing unpaired electrons are paramagnetic in nature whereas those possessing electron pairs are diamagnetic in nature. Reason: In diamagnetic substances, the spins of the two electrons cancel out and thus the diamagnetic substances doesnot show any magnetic behaviour . However in paramagnetic substances, the spin of the electron counts and the resultant magnetic moment is not zero.
Q.
Assertion (A):
N
O
2
is paramagnetic molecule, whereas
N
2
O
4
is diamagnetic
Reason (R): Molecules with unpaired electrons are Diamagnetic.
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Standard XII Chemistry
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