Question

Which of the following is/are true about the given shorthand notation of electrode potential?
$E_{Cd\left(s\right)/C{d}^{2+}\left(aq\right)}^o=0.40V$

• A. Standard oxidation potential is $0.40V$
• B. Standard reduction potential is $0.40V$
• C. Electrode reaction is
  $Cd\left(s\right)\to C{d}^{2+}\left(aq\right)+2e^{-}$
• D. Electrode reaction is
  $C{d}^{2+}\left(aq\right)+2e^{-}\to Cd\left(s\right)$

Answer 1

Answer: (A), (C)

Electrode reaction is

$Cd\left(s\right)\to C{d}^{2+}\left(aq\right)+2e^{-}$
Electrode potential for oxidation half cell reaction is called oxidation potential. The corresponding electrode is termed as negative electrode.

From the shorthand notation, it is clear that $Cd\left(s\right)$ is oxidised to $C{d}^{2+}\left(aq\right)$ at standard condition.
So, the oxidation half cell reaction is
$Cd\left(s\right)\to C{d}^{2+}\left(aq\right)+2e^{-}$

Hence, it is the standard oxidation potential of the electrode.