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Quantum Numbers

Which of the ...

Question

Which of the following is correct for 2p-orbitals?

n = 1, l = 2

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n = 1

l = 0

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n = 2

l = 0

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n = 2

l = 1

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Solution

The correct option is B $n = 2$ , $l = 1$
Principal quantum number for 2p-orbitals (n) is 2.
Azimuthal quantum number for 2p-orbitals (l) is 1.

Suggest Corrections

Similar questions

(1) n = 1, l = 0, m = 0

(2) n = 2, l = 1, m = -1

(3) n = 2, l = 1, m = +1

(4) n = 3, l = 2, m = +1

(5) n = 3, l = 2, m = 0

n = 1, l = 0, m = 0

n = 2, l = 0, m = 0

n = 2, l = 1, m = 1

n = 3, l = 2, m = 1

n = 3, l = 2, m = 0

n = 0

l = 0

m_{1} = 0

m_{s} = + 1 / 2

n = 1

l = 0

m_{1} = 0

m_{s} = - 1 / 2

n = 1

l = 1

m_{1} = 0

m_{s} = + 1 / 2

n = 2

l = 1

m_{1} = 0

m_{s} = - 1 / 2

n = 2

l = 3

m_{1} = - 3

m_{s} = + 1 / 2

n = 3

l = 1

m_{1} = 0

m_{s} = + 1 / 2

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