Question

Which of the following is correct regarding the bond order in $S{O}_4^{2-}$ ion?

• A. 3/2
• B. 5/4
• C. 4/3
• D. 2

Answer 1

The correct option is A 3/2

Bond order = $\frac{\text{Total number of bonds formed between two atoms in all structures}}{\text{Total number of resonating structures}}$

There are a total 6 resonating structures of $S{O}_4^{2-}$.


Hence,
Bond order = $\frac{2+2+1+2+1+1}{6}=\frac{9}{6}$ = 3/2