You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxides of Sulphur

Which of the ...

Question

Which of the following is correct representation of reaction of acidified permanganate solution with sulphur dioxide?

M n O_{4}

+ 5

S O_{2}

H_{2} O

\to

S O_{4}^{2 -}

M n^{2 +}

H^{+}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M n O

S O_{2}

+ 2

H_{2} O

\to

S

M n^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n O_{4}

+ 5

S O_{2}

+ 2

H_{2} O

\to

S O_{2}

S

+ 2

M n^{2 +}

+ 4

H^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M n O_{4}

+ 2

S O_{2}

+ 2

H_{2} O

\to

S

+ 3

M n^{2 +}

+ 4

H^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 2 $M n O_{4}$ + 5 $S O_{2}$ +2 $H_{2} O$ $\to$ 5 $S O_{4}^{2 -}$ +2 $M n^{2 +}$ +4 $H^{+}$
Acidified potassium permanganate is an oxidising agent. Here, it oxidizes sulphur dioxide to sulpahte ion.
${2 M n O_{4}}^{-} + 5 S O_{2} + 2 H_{2} O ⟶ 5 S O_{4}^{2 -} + 2 M n^{2 +} + 4 H^{+}$

Suggest Corrections

Similar questions

C r_{2} O_{7}^{2 -} + H^{+} + I^{-} \to C r^{3 +} + I_{2} + H_{2} O

C r_{2} O_{7}^{2 -} + F e_{2}^{+} + H^{+} \to C r^{3 +} + F e^{3 +} + H_{2} O

M n O^{4 -} + S O_{3}^{2 -} + H^{+} \to M n^{2 +} + S O_{4}^{2 -} + H_{2} O

M n O^{4 -} + H^{+} + B r^{-} \to M n^{2 +} + B r_{2} + H_{2} O

M n O_{4}^{-} + S O_{2} ⟶ S O_{4}^{2 -} + {M n}^{2 +}

M n O_{4}^{-} + C_{2} O_{4}^{- 2} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$ the reductant is

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ which is the reducing agent?

Join BYJU'S Learning Program