Which of the following is equivalent to $8 (x - 2) < 3 x - 6$ ?

x < 2

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x > 2

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x \geq - 2

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x < - 2

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x > - 2

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Solution

The correct option is A $x < 2$
Given, $8 (x - 2) < 3 x - 6$
$\Rightarrow 8 x - 16 < 3 x - 6$
$\Rightarrow 8 x - 3 x < 16 - 6$
$\Rightarrow 5 x < 10$
$\Rightarrow x < \frac{10}{5}$
$\Rightarrow x < 2$

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